x^2-68x-68=0

Solution for x^2-68x-68=0 equation:

x^2-68x-68=0

a = 1; b = -68; c = -68;
Δ = b2-4ac
Δ = -682-4·1·(-68)
Δ = 4896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4896}=\sqrt{144*34}=\sqrt{144}*\sqrt{34}=12\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-12\sqrt{34}}{2*1}=\frac{68-12\sqrt{34}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+12\sqrt{34}}{2*1}=\frac{68+12\sqrt{34}}{2}
$